Find the equation of family of circles through the intersection of x 2 + y 2 − 6 x + 2 y + 4 = 0 and x 2 + y 2 + 2 x − 4 y − 6 = 0 whose center lies on y = x. View Solution Q 5
Simplify 3x^2(2xy-3xy^2+4x^2y^3) Step 1. Apply the distributive property. Step 2. Simplify. Tap for more steps Step 2.1. Multiply by by adding the exponents.
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7x 4y 2 2x 2y 5
